Distance from Sissonville, West Virginia to Lawrence Creek, Oklahoma
Wondering how far is Lawrence Creek, Oklahoma from Sissonville, West Virginia? Here's our driving distance calculation from Sissonville to Lawrence Creek.
The driving distance between Sissonville, West Virginia and Lawrence Creek, Oklahoma is 940 mi or 1513 km . It takes 13 hr 50 min to reach Lawrence Creek from Sissonville by road. The distance by air route is 829 mi / 1334 km.
There are 3 routes to reach Lawrence Creek, Oklahoma from Sissonville, West Virginia.
940 mi / 1513 km - 13 hr 50 min
945 mi / 1521 km - 14 hr 22 min
974 mi / 1568 km - 14 hr 38 min
Sissonville, West Virginia
Time | 18:18:48 |
Latitude | 38.5281485 |
Longitude | -81.6309601 |
State | West Virginia |
Zip | |
Timezone | America/Indiana/Vevay |
Lawrence Creek, Oklahoma
Time | 18:18:48 |
Latitude | 36.0850737 |
Longitude | -96.4252918 |
State | Oklahoma |
Zip | 74044 |
Timezone | America/Indiana/Vincennes |
Sissonville Distance to Popular Cities
Route | Distance |
---|---|
Sissonville to Eskdale | 41 mi / 66 km |
Sissonville to Pax | 61 mi / 98 km |
Sissonville to Scarbro | 64 mi / 103 km |
Sissonville to Oak Hill | 65 mi / 105 km |
Sissonville to Hilltop | 66 mi / 106 km |
Sissonville to Glen Jean | 66 mi / 106 km |
Sissonville to Mt Hope | 68 mi / 109 km |
Sissonville to Prosperity | 71 mi / 114 km |
Sissonville to Bradley | 71 mi / 114 km |
Sissonville to Gatewood | 72 mi / 116 km |
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