Distance from Sissonville, West Virginia to Linton, North Dakota
Wondering how far is Linton, North Dakota from Sissonville, West Virginia? Here's our driving distance calculation from Sissonville to Linton.
The driving distance between Sissonville, West Virginia and Linton, North Dakota is 1293 mi or 2081 km . It takes 19 hr 36 min to reach Linton from Sissonville by road. The distance by air route is 1085 mi / 1746 km.
There are 2 routes to reach Linton, North Dakota from Sissonville, West Virginia.
1293 mi / 2081 km - 19 hr 36 min
1270 mi / 2044 km - 19 hr 48 min
Sissonville, West Virginia
| Time | 17:29:02 |
| Latitude | 38.5281485 |
| Longitude | -81.6309601 |
| State | West Virginia |
| Zip | |
| Timezone | America/Indiana/Vevay |
Linton, North Dakota
| Time | 16:29:02 |
| Latitude | 46.2666567 |
| Longitude | -100.2328917 |
| State | North Dakota |
| Zip | 58552 |
| Timezone | America/North_Dakota/New_Salem |
Sissonville Distance to Popular Cities
| Route | Distance |
|---|---|
| Sissonville to Eskdale | 41 mi / 66 km |
| Sissonville to Pax | 61 mi / 98 km |
| Sissonville to Scarbro | 64 mi / 103 km |
| Sissonville to Oak Hill | 65 mi / 105 km |
| Sissonville to Hilltop | 66 mi / 106 km |
| Sissonville to Glen Jean | 66 mi / 106 km |
| Sissonville to Mt Hope | 68 mi / 109 km |
| Sissonville to Prosperity | 71 mi / 114 km |
| Sissonville to Bradley | 71 mi / 114 km |
| Sissonville to Gatewood | 72 mi / 116 km |
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