Distance from Sissonville, West Virginia to Lunenburg, Vermont
Wondering how far is Lunenburg, Vermont from Sissonville, West Virginia? Here's our driving distance calculation from Sissonville to Lunenburg.
The driving distance between Sissonville, West Virginia and Lunenburg, Vermont is 888 mi or 1429 km . It takes 13 hr 32 min to reach Lunenburg from Sissonville by road. The distance by air route is 657 mi / 1057 km.
There are 3 routes to reach Lunenburg, Vermont from Sissonville, West Virginia.
888 mi / 1429 km - 13 hr 32 min
903 mi / 1453 km - 13 hr 41 min
903 mi / 1453 km - 13 hr 51 min
Sissonville, West Virginia
| Time | 17:28:54 |
| Latitude | 38.5281485 |
| Longitude | -81.6309601 |
| State | West Virginia |
| Zip | |
| Timezone | America/Indiana/Vevay |
Lunenburg, Vermont
| Time | 17:28:54 |
| Latitude | 44.4631136 |
| Longitude | -71.6820321 |
| State | Vermont |
| Zip | |
| Timezone | America/New_York |
Sissonville Distance to Popular Cities
| Route | Distance |
|---|---|
| Sissonville to Eskdale | 41 mi / 66 km |
| Sissonville to Pax | 61 mi / 98 km |
| Sissonville to Scarbro | 64 mi / 103 km |
| Sissonville to Oak Hill | 65 mi / 105 km |
| Sissonville to Hilltop | 66 mi / 106 km |
| Sissonville to Glen Jean | 66 mi / 106 km |
| Sissonville to Mt Hope | 68 mi / 109 km |
| Sissonville to Prosperity | 71 mi / 114 km |
| Sissonville to Bradley | 71 mi / 114 km |
| Sissonville to Gatewood | 72 mi / 116 km |
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