Distance from Sissonville, West Virginia to Lynndyl, Utah
Wondering how far is Lynndyl, Utah from Sissonville, West Virginia? Here's our driving distance calculation from Sissonville to Lynndyl.
The driving distance between Sissonville, West Virginia and Lynndyl, Utah is 1894 mi or 3048 km . It takes 28 hr to reach Lynndyl from Sissonville by road. The distance by air route is 1644 mi / 2646 km.
There are 3 routes to reach Lynndyl, Utah from Sissonville, West Virginia.
1894 mi / 3048 km - 28 hr
1922 mi / 3093 km - 28 hr
1943 mi / 3127 km - 29 hr
Sissonville, West Virginia
| Time | 18:13:53 |
| Latitude | 38.5281485 |
| Longitude | -81.6309601 |
| State | West Virginia |
| Zip | |
| Timezone | America/Indiana/Vevay |
Lynndyl, Utah
| Time | 16:13:53 |
| Latitude | 39.519119 |
| Longitude | -112.3757785 |
| State | Utah |
| Zip | 84640 |
| Timezone | America/Boise |
Sissonville Distance to Popular Cities
| Route | Distance |
|---|---|
| Sissonville to Eskdale | 41 mi / 66 km |
| Sissonville to Pax | 61 mi / 98 km |
| Sissonville to Scarbro | 64 mi / 103 km |
| Sissonville to Oak Hill | 65 mi / 105 km |
| Sissonville to Hilltop | 66 mi / 106 km |
| Sissonville to Glen Jean | 66 mi / 106 km |
| Sissonville to Mt Hope | 68 mi / 109 km |
| Sissonville to Prosperity | 71 mi / 114 km |
| Sissonville to Bradley | 71 mi / 114 km |
| Sissonville to Gatewood | 72 mi / 116 km |
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