Distance from Sissonville, West Virginia to Marvin, South Dakota
Wondering how far is Marvin, South Dakota from Sissonville, West Virginia? Here's our driving distance calculation from Sissonville to Marvin.
The driving distance between Sissonville, West Virginia and Marvin, South Dakota is 1109 mi or 1785 km . It takes 17 hr to reach Marvin from Sissonville by road. The distance by air route is 911 mi / 1466 km.
There are 3 routes to reach Marvin, South Dakota from Sissonville, West Virginia.
1109 mi / 1785 km - 17 hr
1086 mi / 1748 km - 17 hr 12 min
1181 mi / 1901 km - 17 hr 48 min
Sissonville, West Virginia
| Time | 17:34:15 |
| Latitude | 38.5281485 |
| Longitude | -81.6309601 |
| State | West Virginia |
| Zip | |
| Timezone | America/Indiana/Vevay |
Marvin, South Dakota
| Time | 16:34:15 |
| Latitude | 45.2613519 |
| Longitude | -96.9125722 |
| State | South Dakota |
| Zip | 57251 |
| Timezone | America/North_Dakota/New_Salem |
Sissonville Distance to Popular Cities
| Route | Distance |
|---|---|
| Sissonville to Eskdale | 41 mi / 66 km |
| Sissonville to Pax | 61 mi / 98 km |
| Sissonville to Scarbro | 64 mi / 103 km |
| Sissonville to Oak Hill | 65 mi / 105 km |
| Sissonville to Hilltop | 66 mi / 106 km |
| Sissonville to Glen Jean | 66 mi / 106 km |
| Sissonville to Mt Hope | 68 mi / 109 km |
| Sissonville to Prosperity | 71 mi / 114 km |
| Sissonville to Bradley | 71 mi / 114 km |
| Sissonville to Gatewood | 72 mi / 116 km |
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