Distance from Sissonville, West Virginia to Max, Nebraska
Wondering how far is Max, Nebraska from Sissonville, West Virginia? Here's our driving distance calculation from Sissonville to Max.
The driving distance between Sissonville, West Virginia and Max, Nebraska is 1210 mi or 1947 km . It takes 17 hr 42 min to reach Max from Sissonville by road. The distance by air route is 1060 mi / 1706 km.
There are 2 routes to reach Max, Nebraska from Sissonville, West Virginia.
1210 mi / 1947 km - 17 hr 42 min
1237 mi / 1991 km - 18 hr 24 min
Sissonville, West Virginia
Time | 04:11:01 |
Latitude | 38.5281485 |
Longitude | -81.6309601 |
State | West Virginia |
Zip | |
Timezone | America/Indiana/Vevay |
Max, Nebraska
Time | 02:11:01 |
Latitude | 40.1138843 |
Longitude | -101.4026645 |
State | Nebraska |
Zip | 69037 |
Timezone | America/Denver |
Sissonville Distance to Popular Cities
Route | Distance |
---|---|
Sissonville to Eskdale | 41 mi / 66 km |
Sissonville to Pax | 61 mi / 98 km |
Sissonville to Scarbro | 64 mi / 103 km |
Sissonville to Oak Hill | 65 mi / 105 km |
Sissonville to Hilltop | 66 mi / 106 km |
Sissonville to Glen Jean | 66 mi / 106 km |
Sissonville to Mt Hope | 68 mi / 109 km |
Sissonville to Prosperity | 71 mi / 114 km |
Sissonville to Bradley | 71 mi / 114 km |
Sissonville to Gatewood | 72 mi / 116 km |
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