Distance from Sissonville, West Virginia to Newkirk, Oklahoma
Wondering how far is Newkirk, Oklahoma from Sissonville, West Virginia? Here's our driving distance calculation from Sissonville to Newkirk.
The driving distance between Sissonville, West Virginia and Newkirk, Oklahoma is 964 mi or 1551 km . It takes 14 hr 29 min to reach Newkirk from Sissonville by road. The distance by air route is 850 mi / 1368 km.
There are 3 routes to reach Newkirk, Oklahoma from Sissonville, West Virginia.
964 mi / 1551 km - 14 hr 29 min
969 mi / 1559 km - 15 hr 2 min
997 mi / 1605 km - 15 hr 18 min
Sissonville, West Virginia
| Time | 04:09:50 |
| Latitude | 38.5281485 |
| Longitude | -81.6309601 |
| State | West Virginia |
| Zip | |
| Timezone | America/Indiana/Vevay |
Newkirk, Oklahoma
| Time | 02:09:50 |
| Latitude | 36.8822549 |
| Longitude | -97.0533717 |
| State | Oklahoma |
| Zip | 74647 |
| Timezone | America/Denver |
Sissonville Distance to Popular Cities
| Route | Distance |
|---|---|
| Sissonville to Eskdale | 41 mi / 66 km |
| Sissonville to Pax | 61 mi / 98 km |
| Sissonville to Scarbro | 64 mi / 103 km |
| Sissonville to Oak Hill | 65 mi / 105 km |
| Sissonville to Hilltop | 66 mi / 106 km |
| Sissonville to Glen Jean | 66 mi / 106 km |
| Sissonville to Mt Hope | 68 mi / 109 km |
| Sissonville to Prosperity | 71 mi / 114 km |
| Sissonville to Bradley | 71 mi / 114 km |
| Sissonville to Gatewood | 72 mi / 116 km |
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