Distance from Sissonville, West Virginia to Philip, South Dakota
Wondering how far is Philip, South Dakota from Sissonville, West Virginia? Here's our driving distance calculation from Sissonville to Philip.
The driving distance between Sissonville, West Virginia and Philip, South Dakota is 1331 mi or 2142 km . It takes 19 hr 26 min to reach Philip from Sissonville by road. The distance by air route is 1104 mi / 1777 km.
There are 3 routes to reach Philip, South Dakota from Sissonville, West Virginia.
1331 mi / 2142 km - 19 hr 26 min
1307 mi / 2103 km - 19 hr 38 min
1397 mi / 2248 km - 20 hr 5 min
Sissonville, West Virginia
| Time | 03:57:02 |
| Latitude | 38.5281485 |
| Longitude | -81.6309601 |
| State | West Virginia |
| Zip | |
| Timezone | America/Indiana/Vevay |
Philip, South Dakota
| Time | 02:57:02 |
| Latitude | 44.0394329 |
| Longitude | -101.6651441 |
| State | South Dakota |
| Zip | 57567 |
| Timezone | America/North_Dakota/New_Salem |
Sissonville Distance to Popular Cities
| Route | Distance |
|---|---|
| Sissonville to Eskdale | 41 mi / 66 km |
| Sissonville to Pax | 61 mi / 98 km |
| Sissonville to Scarbro | 64 mi / 103 km |
| Sissonville to Oak Hill | 65 mi / 105 km |
| Sissonville to Hilltop | 66 mi / 106 km |
| Sissonville to Glen Jean | 66 mi / 106 km |
| Sissonville to Mt Hope | 68 mi / 109 km |
| Sissonville to Prosperity | 71 mi / 114 km |
| Sissonville to Bradley | 71 mi / 114 km |
| Sissonville to Gatewood | 72 mi / 116 km |
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