Distance from Sissonville, West Virginia to Prospect, Louisiana
Wondering how far is Prospect, Louisiana from Sissonville, West Virginia? Here's our driving distance calculation from Sissonville to Prospect.
The driving distance between Sissonville, West Virginia and Prospect, Louisiana is 946 mi or 1522 km . It takes 14 hr 56 min to reach Prospect from Sissonville by road. The distance by air route is 784 mi / 1262 km.
There are 3 routes to reach Prospect, Louisiana from Sissonville, West Virginia.
946 mi / 1522 km - 14 hr 56 min
1007 mi / 1621 km - 15 hr 1 min
1088 mi / 1751 km - 16 hr 23 min
Sissonville, West Virginia
| Time | 04:08:27 |
| Latitude | 38.5281485 |
| Longitude | -81.6309601 |
| State | West Virginia |
| Zip | |
| Timezone | America/Indiana/Vevay |
Prospect, Louisiana
| Time | 03:08:27 |
| Latitude | 31.4504564 |
| Longitude | -92.4876396 |
| State | Louisiana |
| Zip | 71423 |
| Timezone | America/Indiana/Tell_City |
Sissonville Distance to Popular Cities
| Route | Distance |
|---|---|
| Sissonville to Eskdale | 41 mi / 66 km |
| Sissonville to Pax | 61 mi / 98 km |
| Sissonville to Scarbro | 64 mi / 103 km |
| Sissonville to Oak Hill | 65 mi / 105 km |
| Sissonville to Hilltop | 66 mi / 106 km |
| Sissonville to Glen Jean | 66 mi / 106 km |
| Sissonville to Mt Hope | 68 mi / 109 km |
| Sissonville to Prosperity | 71 mi / 114 km |
| Sissonville to Bradley | 71 mi / 114 km |
| Sissonville to Gatewood | 72 mi / 116 km |
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