Distance from Sissonville, West Virginia to Putnam, Oklahoma
Wondering how far is Putnam, Oklahoma from Sissonville, West Virginia? Here's our driving distance calculation from Sissonville to Putnam.
The driving distance between Sissonville, West Virginia and Putnam, Oklahoma is 1125 mi or 1811 km . It takes 16 hr 23 min to reach Putnam from Sissonville by road. The distance by air route is 970 mi / 1561 km.
There are 3 routes to reach Putnam, Oklahoma from Sissonville, West Virginia.
1125 mi / 1811 km - 16 hr 23 min
1129 mi / 1817 km - 16 hr 56 min
1158 mi / 1864 km - 17 hr 12 min
Sissonville, West Virginia
Time | 17:28:51 |
Latitude | 38.5281485 |
Longitude | -81.6309601 |
State | West Virginia |
Zip | |
Timezone | America/Indiana/Vevay |
Putnam, Oklahoma
Time | 15:28:51 |
Latitude | 35.8556011 |
Longitude | -98.9684274 |
State | Oklahoma |
Zip | |
Timezone | America/Denver |
Sissonville Distance to Popular Cities
Route | Distance |
---|---|
Sissonville to Eskdale | 41 mi / 66 km |
Sissonville to Pax | 61 mi / 98 km |
Sissonville to Scarbro | 64 mi / 103 km |
Sissonville to Oak Hill | 65 mi / 105 km |
Sissonville to Hilltop | 66 mi / 106 km |
Sissonville to Glen Jean | 66 mi / 106 km |
Sissonville to Mt Hope | 68 mi / 109 km |
Sissonville to Prosperity | 71 mi / 114 km |
Sissonville to Bradley | 71 mi / 114 km |
Sissonville to Gatewood | 72 mi / 116 km |
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