Distance from Sissonville, West Virginia to Sawyer, North Dakota
Wondering how far is Sawyer, North Dakota from Sissonville, West Virginia? Here's our driving distance calculation from Sissonville to Sawyer.
The driving distance between Sissonville, West Virginia and Sawyer, North Dakota is 1383 mi or 2226 km . It takes 20 hr 38 min to reach Sawyer from Sissonville by road. The distance by air route is 1174 mi / 1889 km.
There are 2 routes to reach Sawyer, North Dakota from Sissonville, West Virginia.
1383 mi / 2226 km - 20 hr 38 min
1359 mi / 2187 km - 20 hr 50 min
Sissonville, West Virginia
Time | 17:35:20 |
Latitude | 38.5281485 |
Longitude | -81.6309601 |
State | West Virginia |
Zip | |
Timezone | America/Indiana/Vevay |
Sawyer, North Dakota
Time | 16:35:20 |
Latitude | 48.0887756 |
Longitude | -101.0543193 |
State | North Dakota |
Zip | 58781 |
Timezone | America/North_Dakota/Beulah |
Sissonville Distance to Popular Cities
Route | Distance |
---|---|
Sissonville to Eskdale | 41 mi / 66 km |
Sissonville to Pax | 61 mi / 98 km |
Sissonville to Scarbro | 64 mi / 103 km |
Sissonville to Oak Hill | 65 mi / 105 km |
Sissonville to Hilltop | 66 mi / 106 km |
Sissonville to Glen Jean | 66 mi / 106 km |
Sissonville to Mt Hope | 68 mi / 109 km |
Sissonville to Prosperity | 71 mi / 114 km |
Sissonville to Bradley | 71 mi / 114 km |
Sissonville to Gatewood | 72 mi / 116 km |
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