Distance from Sissonville, West Virginia to Seward, Kansas
Wondering how far is Seward, Kansas from Sissonville, West Virginia? Here's our driving distance calculation from Sissonville to Seward.
The driving distance between Sissonville, West Virginia and Seward, Kansas is 1033 mi or 1662 km . It takes 15 hr 14 min to reach Seward from Sissonville by road. The distance by air route is 929 mi / 1495 km.
There are 2 routes to reach Seward, Kansas from Sissonville, West Virginia.
1033 mi / 1662 km - 15 hr 14 min
1060 mi / 1706 km - 15 hr 57 min
Sissonville, West Virginia
| Time | 03:58:06 |
| Latitude | 38.5281485 |
| Longitude | -81.6309601 |
| State | West Virginia |
| Zip | |
| Timezone | America/Indiana/Vevay |
Seward, Kansas
| Time | 01:58:06 |
| Latitude | 38.1777913 |
| Longitude | -98.7948107 |
| State | Kansas |
| Zip | 67576 |
| Timezone | America/Denver |
Sissonville Distance to Popular Cities
| Route | Distance |
|---|---|
| Sissonville to Eskdale | 41 mi / 66 km |
| Sissonville to Pax | 61 mi / 98 km |
| Sissonville to Scarbro | 64 mi / 103 km |
| Sissonville to Oak Hill | 65 mi / 105 km |
| Sissonville to Hilltop | 66 mi / 106 km |
| Sissonville to Glen Jean | 66 mi / 106 km |
| Sissonville to Mt Hope | 68 mi / 109 km |
| Sissonville to Prosperity | 71 mi / 114 km |
| Sissonville to Bradley | 71 mi / 114 km |
| Sissonville to Gatewood | 72 mi / 116 km |
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