Distance from Sissonville, West Virginia to Springer, Oklahoma
Wondering how far is Springer, Oklahoma from Sissonville, West Virginia? Here's our driving distance calculation from Sissonville to Springer.
The driving distance between Sissonville, West Virginia and Springer, Oklahoma is 1101 mi or 1772 km . It takes 16 hr 1 min to reach Springer from Sissonville by road. The distance by air route is 909 mi / 1463 km.
There are 3 routes to reach Springer, Oklahoma from Sissonville, West Virginia.
1101 mi / 1772 km - 16 hr 1 min
1118 mi / 1799 km - 16 hr 31 min
1134 mi / 1825 km - 16 hr 50 min
Sissonville, West Virginia
| Time | 04:17:12 |
| Latitude | 38.5281485 |
| Longitude | -81.6309601 |
| State | West Virginia |
| Zip | |
| Timezone | America/Indiana/Vevay |
Springer, Oklahoma
| Time | 02:17:12 |
| Latitude | 34.3145355 |
| Longitude | -97.1427939 |
| State | Oklahoma |
| Zip | |
| Timezone | America/Denver |
Sissonville Distance to Popular Cities
| Route | Distance |
|---|---|
| Sissonville to Eskdale | 41 mi / 66 km |
| Sissonville to Pax | 61 mi / 98 km |
| Sissonville to Scarbro | 64 mi / 103 km |
| Sissonville to Oak Hill | 65 mi / 105 km |
| Sissonville to Hilltop | 66 mi / 106 km |
| Sissonville to Glen Jean | 66 mi / 106 km |
| Sissonville to Mt Hope | 68 mi / 109 km |
| Sissonville to Prosperity | 71 mi / 114 km |
| Sissonville to Bradley | 71 mi / 114 km |
| Sissonville to Gatewood | 72 mi / 116 km |
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