Distance from Sissonville, West Virginia to Surrey, North Dakota
Wondering how far is Surrey, North Dakota from Sissonville, West Virginia? Here's our driving distance calculation from Sissonville to Surrey.
The driving distance between Sissonville, West Virginia and Surrey, North Dakota is 1399 mi or 2251 km . It takes 20 hr 53 min to reach Surrey from Sissonville by road. The distance by air route is 1182 mi / 1902 km.
There are 1 routes to reach Surrey, North Dakota from Sissonville, West Virginia.
1399 mi / 2251 km - 20 hr 53 min
Sissonville, West Virginia
| Time | 04:20:00 |
| Latitude | 38.5281485 |
| Longitude | -81.6309601 |
| State | West Virginia |
| Zip | |
| Timezone | America/Indiana/Vevay |
Surrey, North Dakota
| Time | 03:20:00 |
| Latitude | 48.2364001 |
| Longitude | -101.1334901 |
| State | North Dakota |
| Zip | |
| Timezone | America/North_Dakota/Beulah |
Sissonville Distance to Popular Cities
| Route | Distance |
|---|---|
| Sissonville to Eskdale | 41 mi / 66 km |
| Sissonville to Pax | 61 mi / 98 km |
| Sissonville to Scarbro | 64 mi / 103 km |
| Sissonville to Oak Hill | 65 mi / 105 km |
| Sissonville to Hilltop | 66 mi / 106 km |
| Sissonville to Glen Jean | 66 mi / 106 km |
| Sissonville to Mt Hope | 68 mi / 109 km |
| Sissonville to Prosperity | 71 mi / 114 km |
| Sissonville to Bradley | 71 mi / 114 km |
| Sissonville to Gatewood | 72 mi / 116 km |
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