Distance from Sissonville, West Virginia to Sykeston, North Dakota
Wondering how far is Sykeston, North Dakota from Sissonville, West Virginia? Here's our driving distance calculation from Sissonville to Sykeston.
The driving distance between Sissonville, West Virginia and Sykeston, North Dakota is 1285 mi or 2068 km . It takes 19 hr 7 min to reach Sykeston from Sissonville by road. The distance by air route is 1086 mi / 1748 km.
There are 2 routes to reach Sykeston, North Dakota from Sissonville, West Virginia.
1285 mi / 2068 km - 19 hr 7 min
1262 mi / 2031 km - 19 hr 19 min
Sissonville, West Virginia
| Time | 04:17:08 |
| Latitude | 38.5281485 |
| Longitude | -81.6309601 |
| State | West Virginia |
| Zip | |
| Timezone | America/Indiana/Vevay |
Sykeston, North Dakota
| Time | 03:17:08 |
| Latitude | 47.4649985 |
| Longitude | -99.3995611 |
| State | North Dakota |
| Zip | 58486 |
| Timezone | America/North_Dakota/Center |
Sissonville Distance to Popular Cities
| Route | Distance |
|---|---|
| Sissonville to Eskdale | 41 mi / 66 km |
| Sissonville to Pax | 61 mi / 98 km |
| Sissonville to Scarbro | 64 mi / 103 km |
| Sissonville to Oak Hill | 65 mi / 105 km |
| Sissonville to Hilltop | 66 mi / 106 km |
| Sissonville to Glen Jean | 66 mi / 106 km |
| Sissonville to Mt Hope | 68 mi / 109 km |
| Sissonville to Prosperity | 71 mi / 114 km |
| Sissonville to Bradley | 71 mi / 114 km |
| Sissonville to Gatewood | 72 mi / 116 km |
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