Distance from Sissonville, West Virginia to Tappen, North Dakota
Wondering how far is Tappen, North Dakota from Sissonville, West Virginia? Here's our driving distance calculation from Sissonville to Tappen.
The driving distance between Sissonville, West Virginia and Tappen, North Dakota is 1270 mi or 2044 km . It takes 18 hr 46 min to reach Tappen from Sissonville by road. The distance by air route is 1077 mi / 1733 km.
There are 2 routes to reach Tappen, North Dakota from Sissonville, West Virginia.
1270 mi / 2044 km - 18 hr 46 min
1246 mi / 2005 km - 18 hr 58 min
Sissonville, West Virginia
| Time | 10:33:51 |
| Latitude | 38.5281485 |
| Longitude | -81.6309601 |
| State | West Virginia |
| Zip | |
| Timezone | America/Indiana/Vevay |
Tappen, North Dakota
| Time | 09:33:51 |
| Latitude | 46.8749848 |
| Longitude | -99.6364965 |
| State | North Dakota |
| Zip | 58487 |
| Timezone | America/North_Dakota/Center |
Sissonville Distance to Popular Cities
| Route | Distance |
|---|---|
| Sissonville to Eskdale | 41 mi / 66 km |
| Sissonville to Pax | 61 mi / 98 km |
| Sissonville to Scarbro | 64 mi / 103 km |
| Sissonville to Oak Hill | 65 mi / 105 km |
| Sissonville to Hilltop | 66 mi / 106 km |
| Sissonville to Glen Jean | 66 mi / 106 km |
| Sissonville to Mt Hope | 68 mi / 109 km |
| Sissonville to Prosperity | 71 mi / 114 km |
| Sissonville to Bradley | 71 mi / 114 km |
| Sissonville to Gatewood | 72 mi / 116 km |
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