Distance from Sissonville, West Virginia to Thornburg, Iowa
Wondering how far is Thornburg, Iowa from Sissonville, West Virginia? Here's our driving distance calculation from Sissonville to Thornburg.
The driving distance between Sissonville, West Virginia and Thornburg, Iowa is 732 mi or 1178 km . It takes 11 hr 14 min to reach Thornburg from Sissonville by road. The distance by air route is 601 mi / 967 km.
There are 2 routes to reach Thornburg, Iowa from Sissonville, West Virginia.
732 mi / 1178 km - 11 hr 14 min
794 mi / 1278 km - 11 hr 47 min
Sissonville, West Virginia
| Time | 10:46:26 |
| Latitude | 38.5281485 |
| Longitude | -81.6309601 |
| State | West Virginia |
| Zip | |
| Timezone | America/Indiana/Vevay |
Thornburg, Iowa
| Time | 09:46:26 |
| Latitude | 41.4547292 |
| Longitude | -92.3357394 |
| State | Iowa |
| Zip | 50136 |
| Timezone | America/Chicago |
Sissonville Distance to Popular Cities
| Route | Distance |
|---|---|
| Sissonville to Eskdale | 41 mi / 66 km |
| Sissonville to Pax | 61 mi / 98 km |
| Sissonville to Scarbro | 64 mi / 103 km |
| Sissonville to Oak Hill | 65 mi / 105 km |
| Sissonville to Hilltop | 66 mi / 106 km |
| Sissonville to Glen Jean | 66 mi / 106 km |
| Sissonville to Mt Hope | 68 mi / 109 km |
| Sissonville to Prosperity | 71 mi / 114 km |
| Sissonville to Bradley | 71 mi / 114 km |
| Sissonville to Gatewood | 72 mi / 116 km |
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