Distance from Sissonville, West Virginia to Trent, South Dakota
Wondering how far is Trent, South Dakota from Sissonville, West Virginia? Here's our driving distance calculation from Sissonville to Trent.
The driving distance between Sissonville, West Virginia and Trent, South Dakota is 1074 mi or 1728 km . It takes 16 hr 5 min to reach Trent from Sissonville by road. The distance by air route is 863 mi / 1389 km.
There are 3 routes to reach Trent, South Dakota from Sissonville, West Virginia.
1074 mi / 1728 km - 16 hr 5 min
1051 mi / 1691 km - 16 hr 17 min
1156 mi / 1860 km - 16 hr 47 min
Sissonville, West Virginia
| Time | 10:53:03 |
| Latitude | 38.5281485 |
| Longitude | -81.6309601 |
| State | West Virginia |
| Zip | |
| Timezone | America/Indiana/Vevay |
Trent, South Dakota
| Time | 09:53:03 |
| Latitude | 43.9063612 |
| Longitude | -96.6539369 |
| State | South Dakota |
| Zip | 57065 |
| Timezone | America/North_Dakota/New_Salem |
Sissonville Distance to Popular Cities
| Route | Distance |
|---|---|
| Sissonville to Eskdale | 41 mi / 66 km |
| Sissonville to Pax | 61 mi / 98 km |
| Sissonville to Scarbro | 64 mi / 103 km |
| Sissonville to Oak Hill | 65 mi / 105 km |
| Sissonville to Hilltop | 66 mi / 106 km |
| Sissonville to Glen Jean | 66 mi / 106 km |
| Sissonville to Mt Hope | 68 mi / 109 km |
| Sissonville to Prosperity | 71 mi / 114 km |
| Sissonville to Bradley | 71 mi / 114 km |
| Sissonville to Gatewood | 72 mi / 116 km |
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