Distance from Sissonville, West Virginia to Walnut Creek, North Carolina
Wondering how far is Walnut Creek, North Carolina from Sissonville, West Virginia? Here's our driving distance calculation from Sissonville to Walnut Creek.
The driving distance between Sissonville, West Virginia and Walnut Creek, North Carolina is 400 mi or 644 km . It takes 6 hr 12 min to reach Walnut Creek from Sissonville by road. The distance by air route is 305 mi / 491 km.
There are 3 routes to reach Walnut Creek, North Carolina from Sissonville, West Virginia.
400 mi / 644 km - 6 hr 12 min
412 mi / 663 km - 6 hr 55 min
420 mi / 676 km - 7 hr 12 min
Sissonville, West Virginia
Time | 15:24:18 |
Latitude | 38.5281485 |
Longitude | -81.6309601 |
State | West Virginia |
Zip | |
Timezone | America/Indiana/Vevay |
Walnut Creek, North Carolina
Time | 15:24:18 |
Latitude | 35.3071071 |
Longitude | -77.8649817 |
State | North Carolina |
Zip | 27534 |
Timezone | America/Kentucky/Monticello |
Sissonville Distance to Popular Cities
Route | Distance |
---|---|
Sissonville to Eskdale | 41 mi / 66 km |
Sissonville to Pax | 61 mi / 98 km |
Sissonville to Scarbro | 64 mi / 103 km |
Sissonville to Oak Hill | 65 mi / 105 km |
Sissonville to Hilltop | 66 mi / 106 km |
Sissonville to Glen Jean | 66 mi / 106 km |
Sissonville to Mt Hope | 68 mi / 109 km |
Sissonville to Prosperity | 71 mi / 114 km |
Sissonville to Bradley | 71 mi / 114 km |
Sissonville to Gatewood | 72 mi / 116 km |
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