Distance from Sissonville, West Virginia to Walnut Creek, California
Wondering how far is Walnut Creek, California from Sissonville, West Virginia? Here's our driving distance calculation from Sissonville to Walnut Creek.
The driving distance between Sissonville, West Virginia and Walnut Creek, California is 2555 mi or 4112 km . It takes 37 hr to reach Walnut Creek from Sissonville by road. The distance by air route is 2177 mi / 3504 km.
There are 3 routes to reach Walnut Creek, California from Sissonville, West Virginia.
2555 mi / 4112 km - 37 hr
2544 mi / 4094 km - 38 hr
2926 mi / 4709 km - 43 hr
Sissonville, West Virginia
| Time | 15:21:50 |
| Latitude | 38.5281485 |
| Longitude | -81.6309601 |
| State | West Virginia |
| Zip | |
| Timezone | America/Indiana/Vevay |
Walnut Creek, California
| Time | 12:21:50 |
| Latitude | 37.9100783 |
| Longitude | -122.0651819 |
| State | California |
| Zip | |
| Timezone | America/Los_Angeles |
Sissonville Distance to Popular Cities
| Route | Distance |
|---|---|
| Sissonville to Eskdale | 41 mi / 66 km |
| Sissonville to Pax | 61 mi / 98 km |
| Sissonville to Scarbro | 64 mi / 103 km |
| Sissonville to Oak Hill | 65 mi / 105 km |
| Sissonville to Hilltop | 66 mi / 106 km |
| Sissonville to Glen Jean | 66 mi / 106 km |
| Sissonville to Mt Hope | 68 mi / 109 km |
| Sissonville to Prosperity | 71 mi / 114 km |
| Sissonville to Bradley | 71 mi / 114 km |
| Sissonville to Gatewood | 72 mi / 116 km |
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