Distance from Sissonville, West Virginia to Waterbury, Connecticut
Wondering how far is Waterbury, Connecticut from Sissonville, West Virginia? Here's our driving distance calculation from Sissonville to Waterbury.
The driving distance between Sissonville, West Virginia and Waterbury, Connecticut is 639 mi or 1028 km . It takes 9 hr 42 min to reach Waterbury from Sissonville by road. The distance by air route is 499 mi / 803 km.
There are 3 routes to reach Waterbury, Connecticut from Sissonville, West Virginia.
639 mi / 1028 km - 9 hr 42 min
648 mi / 1043 km - 9 hr 48 min
700 mi / 1127 km - 10 hr 40 min
Sissonville, West Virginia
Time | 15:26:40 |
Latitude | 38.5281485 |
Longitude | -81.6309601 |
State | West Virginia |
Zip | |
Timezone | America/Indiana/Vevay |
Waterbury, Connecticut
Time | 15:26:40 |
Latitude | 41.5581525 |
Longitude | -73.0514965 |
State | Connecticut |
Zip | |
Timezone | America/New_York |
Sissonville Distance to Popular Cities
Route | Distance |
---|---|
Sissonville to Eskdale | 41 mi / 66 km |
Sissonville to Pax | 61 mi / 98 km |
Sissonville to Scarbro | 64 mi / 103 km |
Sissonville to Oak Hill | 65 mi / 105 km |
Sissonville to Hilltop | 66 mi / 106 km |
Sissonville to Glen Jean | 66 mi / 106 km |
Sissonville to Mt Hope | 68 mi / 109 km |
Sissonville to Prosperity | 71 mi / 114 km |
Sissonville to Bradley | 71 mi / 114 km |
Sissonville to Gatewood | 72 mi / 116 km |
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