Distance from Sissonville, West Virginia to Waubay, South Dakota
Wondering how far is Waubay, South Dakota from Sissonville, West Virginia? Here's our driving distance calculation from Sissonville to Waubay.
The driving distance between Sissonville, West Virginia and Waubay, South Dakota is 1131 mi or 1820 km . It takes 17 hr 19 min to reach Waubay from Sissonville by road. The distance by air route is 930 mi / 1497 km.
There are 3 routes to reach Waubay, South Dakota from Sissonville, West Virginia.
1131 mi / 1820 km - 17 hr 19 min
1107 mi / 1782 km - 17 hr 31 min
1194 mi / 1922 km - 17 hr 58 min
Sissonville, West Virginia
| Time | 17:23:24 |
| Latitude | 38.5281485 |
| Longitude | -81.6309601 |
| State | West Virginia |
| Zip | |
| Timezone | America/Indiana/Vevay |
Waubay, South Dakota
| Time | 16:23:24 |
| Latitude | 45.3319041 |
| Longitude | -97.3050847 |
| State | South Dakota |
| Zip | 57273 |
| Timezone | America/North_Dakota/New_Salem |
Sissonville Distance to Popular Cities
| Route | Distance |
|---|---|
| Sissonville to Eskdale | 41 mi / 66 km |
| Sissonville to Pax | 61 mi / 98 km |
| Sissonville to Scarbro | 64 mi / 103 km |
| Sissonville to Oak Hill | 65 mi / 105 km |
| Sissonville to Hilltop | 66 mi / 106 km |
| Sissonville to Glen Jean | 66 mi / 106 km |
| Sissonville to Mt Hope | 68 mi / 109 km |
| Sissonville to Prosperity | 71 mi / 114 km |
| Sissonville to Bradley | 71 mi / 114 km |
| Sissonville to Gatewood | 72 mi / 116 km |
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