Distance from Sissonville, West Virginia to Winner, South Dakota
Wondering how far is Winner, South Dakota from Sissonville, West Virginia? Here's our driving distance calculation from Sissonville to Winner.
The driving distance between Sissonville, West Virginia and Winner, South Dakota is 1168 mi or 1880 km . It takes 18 hr 6 min to reach Winner from Sissonville by road. The distance by air route is 1006 mi / 1619 km.
There are 3 routes to reach Winner, South Dakota from Sissonville, West Virginia.
1168 mi / 1880 km - 18 hr 6 min
1190 mi / 1915 km - 18 hr 11 min
1247 mi / 2007 km - 18 hr 37 min
Sissonville, West Virginia
| Time | 04:16:27 |
| Latitude | 38.5281485 |
| Longitude | -81.6309601 |
| State | West Virginia |
| Zip | |
| Timezone | America/Indiana/Vevay |
Winner, South Dakota
| Time | 03:16:27 |
| Latitude | 43.3766665 |
| Longitude | -99.8590069 |
| State | South Dakota |
| Zip | 57580 |
| Timezone | America/North_Dakota/New_Salem |
Sissonville Distance to Popular Cities
| Route | Distance |
|---|---|
| Sissonville to Eskdale | 41 mi / 66 km |
| Sissonville to Pax | 61 mi / 98 km |
| Sissonville to Scarbro | 64 mi / 103 km |
| Sissonville to Oak Hill | 65 mi / 105 km |
| Sissonville to Hilltop | 66 mi / 106 km |
| Sissonville to Glen Jean | 66 mi / 106 km |
| Sissonville to Mt Hope | 68 mi / 109 km |
| Sissonville to Prosperity | 71 mi / 114 km |
| Sissonville to Bradley | 71 mi / 114 km |
| Sissonville to Gatewood | 72 mi / 116 km |
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