Distance from Spout Springs, North Carolina to Sasakwa, Oklahoma

Wondering how far is Sasakwa, Oklahoma from Spout Springs, North Carolina? Here's our driving distance calculation from Spout Springs to Sasakwa.

Distance
1184 mi
1905 km
Travel Time
17 hr 20 min

The driving distance between Spout Springs, North Carolina and Sasakwa, Oklahoma is 1184 mi or 1905 km . It takes 17 hr 20 min to reach Sasakwa from Spout Springs by road. The distance by air route is 986 mi / 1587 km.

There are 3 routes to reach Sasakwa, Oklahoma from Spout Springs, North Carolina.

Via I-40 W and I-40
1184 mi / 1905 km - 17 hr 20 min
Via I-20 W and I-40 W
1220 mi / 1963 km - 17 hr 39 min
Via I-40 W
1242 mi / 1999 km - 18 hr 48 min

Spout Springs, North Carolina

Time 07:26:57
Latitude 35.26944
Longitude -79.06
State North Carolina
Zip 28326
Timezone America/Kentucky/Monticello

Sasakwa, Oklahoma

Time 07:26:57
Latitude 34.9486951
Longitude -96.525289
State Oklahoma
Zip 74867
Timezone America/Indiana/Vincennes

Nearby Cities

Stem

87 mi / 140 km

Henderson

107 mi / 172 km

Clover

144 mi / 232 km

Union Level

138 mi / 222 km

La Crosse

139 mi / 224 km

South Hill

139 mi / 224 km

Ebony

140 mi / 225 km

Lawrenceville

154 mi / 248 km

Victoria

165 mi / 266 km

Charlotte Court House

157 mi / 253 km

Spout Springs Distance to Popular Cities

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