Distance from Troy, Indiana to Simonton Lake, Indiana
Wondering how far is Simonton Lake, Indiana from Troy, Indiana? Here's our driving distance calculation from Troy to Simonton Lake.
The driving distance between Troy, Indiana and Simonton Lake, Indiana is 318 mi or 512 km . It takes 5 hr 26 min to reach Simonton Lake from Troy by road. The distance by air route is 263 mi / 423 km.
There are 2 routes to reach Simonton Lake, Indiana from Troy, Indiana.
318 mi / 512 km - 5 hr 26 min
335 mi / 539 km - 5 hr 48 min
Troy, Indiana
Time | 02:01:47 |
Latitude | 37.9953335 |
Longitude | -86.7977672 |
State | Indiana |
Zip | |
Timezone | America/Indiana/Tell_City |
Simonton Lake, Indiana
Time | 02:01:47 |
Latitude | 41.7542159 |
Longitude | -85.9750012 |
State | Indiana |
Zip | 46514 |
Timezone | America/Indiana/Knox |
Nearby Cities
Ferdinand
18 mi / 29 km
Huntingburg
28 mi / 45 km
Birdseye
28 mi / 45 km
Holland
30 mi / 48 km
Jasper
32 mi / 51 km
Alton
32 mi / 51 km
Dubois
40 mi / 64 km
Leavenworth
43 mi / 69 km
Otwell
43 mi / 69 km
Spurgeon
47 mi / 76 km
Troy Distance to Popular Cities
Route | Distance |
---|---|
Troy to Ferdinand | 18 mi / 29 km |
Troy to Huntingburg | 28 mi / 45 km |
Troy to Birdseye | 28 mi / 45 km |
Troy to Holland | 30 mi / 48 km |
Troy to Jasper | 32 mi / 51 km |
Troy to Alton | 32 mi / 51 km |
Troy to Dubois | 40 mi / 64 km |
Troy to Leavenworth | 43 mi / 69 km |
Troy to Otwell | 43 mi / 69 km |
Troy to Spurgeon | 47 mi / 76 km |
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