Distance from Wallace Ridge, Louisiana to Sebastopol, California

Wondering how far is Sebastopol, California from Wallace Ridge, Louisiana? Here's our driving distance calculation from Wallace Ridge to Sebastopol.

Distance
2128 mi
3425 km
Travel Time
31 hr

The driving distance between Wallace Ridge, Louisiana and Sebastopol, California is 2128 mi or 3425 km . It takes 31 hr to reach Sebastopol from Wallace Ridge by road. The distance by air route is 1804 mi / 2903 km.

There are 3 routes to reach Sebastopol, California from Wallace Ridge, Louisiana.

Via I-40 W
2128 mi / 3425 km - 31 hr
Via I-20 W and I-10 W
2218 mi / 3570 km - 33 hr
Via I-10 W
2265 mi / 3645 km - 34 hr

Wallace Ridge, Louisiana

Time 09:14:47
Latitude 31.708973
Longitude -91.827309
State Louisiana
Zip 71343
Timezone America/Indiana/Tell_City

Sebastopol, California

Time 07:14:47
Latitude 38.4021359
Longitude -122.8238806
State California
Zip 95472
Timezone America/Los_Angeles

Nearby Cities

Sachse

360 mi / 579 km

Murphy

365 mi / 587 km

Addison

363 mi / 584 km

Hebron

371 mi / 597 km

Little Elm

380 mi / 612 km

Hackberry

380 mi / 612 km

Lake Dallas

382 mi / 615 km

Highland Village

384 mi / 618 km

Corinth

385 mi / 620 km

Lakewood Village

386 mi / 621 km

Wallace Ridge Distance to Popular Cities

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