Distance from Waterbury, Connecticut to Seymour, Tennessee

Wondering how far is Seymour, Tennessee from Waterbury, Connecticut? Here's our driving distance calculation from Waterbury to Seymour.

Distance
797 mi
1283 km
Travel Time
12 hr 8 min

The driving distance between Waterbury, Connecticut and Seymour, Tennessee is 797 mi or 1283 km . It takes 12 hr 8 min to reach Seymour from Waterbury by road. The distance by air route is 698 mi / 1123 km.

There are 2 routes to reach Seymour, Tennessee from Waterbury, Connecticut.

Via I-81 S
797 mi / 1283 km - 12 hr 8 min
Via I-68 W and I-81 S
886 mi / 1426 km - 13 hr 41 min

Waterbury, Connecticut

Time 22:01:40
Latitude 41.5581525
Longitude -73.0514965
State Connecticut
Zip
Timezone America/New_York

Seymour, Tennessee

Time 22:01:40
Latitude 35.8725599
Longitude -83.7740198
State Tennessee
Zip
Timezone America/Kentucky/Monticello

Nearby Cities

Peach Lake

36 mi / 58 km

West Point

72 mi / 116 km

Saugerties South

99 mi / 159 km

Suffern

84 mi / 135 km

Montebello

84 mi / 135 km

Queens

90 mi / 145 km

Viola

85 mi / 137 km

Hillburn

87 mi / 140 km

Tuxedo Park

95 mi / 153 km

Elmont

94 mi / 151 km

Waterbury Distance to Popular Cities

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