Distance from Waterville, Washington to Oxbow, North Dakota
Wondering how far is Oxbow, North Dakota from Waterville, Washington? Here's our driving distance calculation from Waterville to Oxbow.
The driving distance between Waterville, Washington and Oxbow, North Dakota is 1292 mi or 2079 km . It takes 19 hr 4 min to reach Oxbow from Waterville by road. The distance by air route is 1091 mi / 1756 km.
There are 3 routes to reach Oxbow, North Dakota from Waterville, Washington.
1292 mi / 2079 km - 19 hr 4 min
1364 mi / 2195 km - 21 hr 13 min
1649 mi / 2654 km - 25 hr
Waterville, Washington
| Time | 00:04:22 |
| Latitude | 47.6470761 |
| Longitude | -120.0711788 |
| State | Washington |
| Zip | 98858 |
| Timezone | America/Boise |
Oxbow, North Dakota
| Time | 01:04:22 |
| Latitude | 46.6699634 |
| Longitude | -96.8003601 |
| State | North Dakota |
| Zip | 58047 |
| Timezone | America/North_Dakota/Center |
Waterville Distance to Popular Cities
| Route | Distance |
|---|---|
| Waterville to Saltese | 238 mi / 383 km |
| Waterville to Haugan | 244 mi / 393 km |
| Waterville to Heron | 247 mi / 398 km |
| Waterville to De Borgia | 247 mi / 398 km |
| Waterville to Noxon | 257 mi / 414 km |
| Waterville to St Regis | 261 mi / 420 km |
| Waterville to Trout Creek | 270 mi / 435 km |
| Waterville to Bull Lake | 271 mi / 436 km |
| Waterville to Troy | 272 mi / 438 km |
| Waterville to Superior | 274 mi / 441 km |
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