Distance from Wrightsville Beach, North Carolina to Sebastopol, California

Wondering how far is Sebastopol, California from Wrightsville Beach, North Carolina? Here's our driving distance calculation from Wrightsville Beach to Sebastopol.

Distance
2952 mi
4751 km
Travel Time
43 hr

The driving distance between Wrightsville Beach, North Carolina and Sebastopol, California is 2952 mi or 4751 km . It takes 43 hr to reach Sebastopol from Wrightsville Beach by road. The distance by air route is 2499 mi / 4022 km.

There are 3 routes to reach Sebastopol, California from Wrightsville Beach, North Carolina.

Via I-40 W
2952 mi / 4751 km - 43 hr
Via I-20 W and I-40 W
2985 mi / 4804 km - 44 hr
Via I-80 W
2990 mi / 4812 km - 44 hr

Wrightsville Beach, North Carolina

Time 21:50:19
Latitude 34.2085036
Longitude -77.7963709
State North Carolina
Zip
Timezone America/Kentucky/Monticello

Sebastopol, California

Time 18:50:19
Latitude 38.4021359
Longitude -122.8238806
State California
Zip 95472
Timezone America/Los_Angeles

Nearby Cities

St James

38 mi / 61 km

Mulberry

182 mi / 293 km

Unionville

189 mi / 304 km

Lake Park

192 mi / 309 km

Hemby Bridge

193 mi / 311 km

Wesley Chapel

196 mi / 315 km

Pineville

210 mi / 338 km

Riverview

223 mi / 359 km

Huntersville

225 mi / 362 km

Westport

233 mi / 375 km

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